Dergiler / Hacettepe Journal of Mathematics and Statistics / 2017 / Cilt: 46 - Sayı: 1

Weakly discontinuous and resolvable functions between topological spaces

Sayfa
103–110
Yayın Tarihi
2022-10-18
DOI
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⚡ TL;DR(1 Cümlede Hızlı Çıkarım)

For functions on metrizable spaces this characterization was announced (without proof) by Vinokurov in 1985.

📌 3 Maddede Bu Makale

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Amaç & Hipotez:We prove that a function $f:X\to Y$ from a first-countable (more generally, Preiss-Simon) space $X$ to a regular space $Y$ is weakly discontinuous (which means that every subspace $A\subset X$ contains an open dense subset $U\subset A$ such that $f|U$ is continuous) if and only if $f$ is open-resolvable (in the sense that for every open subset $U\subset Y$ the preimage $f^{-1}(U)$ is a resolvable subset of $X$) if and only if $f$ is resolvable (in the sense that for every resolvable subset $R\subset Y$ the preimage $f^{-1}(R)$ is a resolvable subset of $X$).
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Temel Bulgular & Veri:We prove that a function $f:X\to Y$ from a first-countable (more generally, Preiss-Simon) space $X$ to a regular space $Y$ is weakly discontinuous (which means that every subspace $A\subset X$ contains an open dense subset $U\subset A$ such that $f|U$ is continuous) if and only if $f$ is open-resolvable (in the sense that for every open subset $U\subset Y$ the preimage $f^{-1}(U)$ is a resolvable subset of $X$) if and only if $f$ is resolvable (in the sense that for every resolvable subset $R\subset Y$ the preimage $f^{-1}(R)$ is a resolvable subset of $X$).
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Sonuç & Katkı:For functions on metrizable spaces this characterization was announced (without proof) by Vinokurov in 1985.
🔬Tür:Araştırma Makalesi
📍Kapsam:Genişletilmiş Akademik Örneklem
⚙️Değişkenler:Weakly discontinuous function · resolvable function · Preiss-Simon space

Abstract

We prove that a function $f:X\to Y$ from a first-countable (more generally, Preiss-Simon) space $X$ to a regular space $Y$ is weakly discontinuous (which means that every subspace $A\subset X$ contains an open dense subset $U\subset A$ such that $f|U$ is continuous) if and only if $f$ is open-resolvable (in the sense that for every open subset $U\subset Y$ the preimage $f^{-1}(U)$ is a resolvable subset of $X$) if and only if $f$ is resolvable (in the sense that for every resolvable subset $R\subset Y$ the preimage $f^{-1}(R)$ is a resolvable subset of $X$). For functions on metrizable spaces this characterization was announced (without proof) by Vinokurov in 1985.

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Bu Makaleye Atıf Yap

BANAKH, T., BOKALO, B. (2022). Weakly discontinuous and resolvable functions between topological spaces. Hacettepe Journal of Mathematics and Statistics, Cilt: 46 - Sayı: 1, 103–110. https://ajindex.com/articles/529911

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Kaynakça (3)

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